#   Find 3 iterations of Newton's method with x0=2 to approximate the
#   solution to f(x)=0 where f(x)=log(x)-x+2.

println("This is Problem 2 for Exam 2.")

xngold=[3.386294361119891,
    3.149938393803694,
    3.1461942570271373 ]

x0=2.0

#  Define any additional functions you need here

function newton(x)

    #  Please add lines to this function and fix
    #  the return value so it's not zero

    return 0
end

correct=0
x=x0
println()
for i=1:3
    global x,correct
    x=newton(x);
    println("x_$(i) = $x")
    if abs(x-xngold[i])<1e-7
        correct+=1
    end
end
println()

if correct!=3
    println("Please try again.  Your answer is incorrect.")
else
    println("Congratulations!  Your answer is correct!")
end